3(x^+1)=5(2x-1)

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Solution for 3(x^+1)=5(2x-1) equation: 



3(x^+1)=5(2x-1)

We move all terms to the left:

3(x^+1)-(5(2x-1))=0

We multiply parentheses

3x-(5(2x-1))+3=0



We calculate terms in parentheses: -(5(2x-1)), so:

5(2x-1)

We multiply parentheses

10x-5

Back to the equation:

-(10x-5)



We get rid of parentheses

3x-10x+5+3=0

We add all the numbers together, and all the variables

-7x+8=0

We move all terms containing x to the left, all other terms to the right

-7x=-8

x=-8/-7

x=1+1/7

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